Rarefaction colliding with two shocks

The Burgers equation {v_t+vv_x =0} is a great illustration of shock formation and propagation, with {v(x,t)} representing velocity at time {t} at position {x}. Let’s consider it with piecewise constant initial condition

\displaystyle u(x,0) = \begin{cases} 1,\quad & x<0 \\ 0,\quad & 0<x<1 \\ 2,\quad & 1<x<2 \\ 0,\quad & x>2 \end{cases}

The equation, rewritten as {(v_t,v_x)\cdot (1,v)=0}, states that the function {v} stays constant on each line of the form {x= x_0 + v(x_0,0)t}. Since we know {v(x_0,0)}, we can go ahead and plot these lines (characteristics). The vertical axis is {t}, horizontal {x}.


Clearly, this picture isn’t complete. The gap near {1} is due to the jump of velocity from {0} to {2}: the particles in front move faster than those in back. This creates a rarefaction wave: the gap gets filled by characteristics emanating from {(1,0)}. They have different slopes, and so the velocity {v} also varies within the rarefaction: it is {v(x,t)=(x-1)/t}, namely the velocity with which one has to travel from {(1,0)} to {(x,t)}.


The intersecting families of characteristics indicate a shock wave. Its propagation speed is the average of two values of {v} to the left and to the right. Let’s draw the shock waves in red.


Characteristics terminate when they run into shock. Truncating the constant-speed characteristics clears up the picture:


This is already accurate up to the time {t=1}. But after that we encounter a complication: the shock wave to the right separates velocity fields of varying intensity, due to rarefaction to the left of the shock. Its propagation is now described by the ODE

\displaystyle \frac{dx}{dt} = \frac12 \left( \frac{x-1}{t} + 0 \right) = \frac{x-1}{2t}

which can be solved easily: {x(t) = 2\sqrt{t} +1}.

Similarly, the shock on the left catches up with rarefaction at {t=2}, and its position after that is found from the ODE

\displaystyle \frac{dx}{dt} = \frac12 \left( 1 + \frac{x-1}{t} \right) = \frac{x-1+t}{2t}

Namely, {x(t) = t-\sqrt{2t}+1} for {t>2}. Let’s plot:


The space-time trajectories of both shocks became curved. Although initially, the shock on the right moved twice as fast as the shock on the left, the rarefaction wave pulls them toward each other. What is this leading to? Yet another collision.

The final collision occurs at the time {t=6+4\sqrt{2} \approx 11.5} when the two shock waves meet. At this moment, rarefaction ceases to exist. The single shock wave forms, separating two constant velocity fields (velocities {1} and {0}). It propagates to the right at constant speed {1/2}. Here is the complete picture of the process:


I don’t know where the holes in the spacetime came from; they aren’t predicted by the Burgers equation.

Leave a Reply

Fill in your details below or click an icon to log in:

WordPress.com Logo

You are commenting using your WordPress.com account. Log Out / Change )

Twitter picture

You are commenting using your Twitter account. Log Out / Change )

Facebook photo

You are commenting using your Facebook account. Log Out / Change )

Google+ photo

You are commenting using your Google+ account. Log Out / Change )

Connecting to %s